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Pochodna funkcji 6sqrt(x^1/3)-4sqrt(x^1/4)

$f\left(x\right) =$	$2{\cdot}\sqrt{3}{\cdot}\sqrt{x}-2{\cdot}\sqrt{x}$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(2{\cdot}\sqrt{3}{\cdot}\sqrt{x}-2{\cdot}\sqrt{x}\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{2{\cdot}\sqrt{3}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sqrt{x}\right)}}-2{\cdot}\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sqrt{x}\right)}}}}$ $=2{\cdot}\sqrt{3}{\cdot}\class{steps-node}{\cssId{steps-node-5}{\dfrac{1}{2{\cdot}\sqrt{x}}}}-2{\cdot}\class{steps-node}{\cssId{steps-node-6}{\dfrac{1}{2{\cdot}\sqrt{x}}}}$ $=\dfrac{\sqrt{3}}{\sqrt{x}}-\dfrac{1}{\sqrt{x}}$

$f\left(x\right) =$

$2{\cdot}\sqrt{3}{\cdot}\sqrt{x}-2{\cdot}\sqrt{x}$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(2{\cdot}\sqrt{3}{\cdot}\sqrt{x}-2{\cdot}\sqrt{x}\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{2{\cdot}\sqrt{3}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sqrt{x}\right)}}-2{\cdot}\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\sqrt{x}\right)}}}}$

$=2{\cdot}\sqrt{3}{\cdot}\class{steps-node}{\cssId{steps-node-5}{\dfrac{1}{2{\cdot}\sqrt{x}}}}-2{\cdot}\class{steps-node}{\cssId{steps-node-6}{\dfrac{1}{2{\cdot}\sqrt{x}}}}$

$=\dfrac{\sqrt{3}}{\sqrt{x}}-\dfrac{1}{\sqrt{x}}$